Math z^2 -15z+36=0 Factor and solve Asked by AnneS2 on 08 Oct 04:51 Last updated by anonymous on 09 Oct 11:27
z^2 -15z+36=0 (z )(z ) ( -12)( -3)=0 (z-12) (z-3) = 0 Solve: (z-12)=0 z-12+12=0+12 z=12 Solve: (z-3) = 0 z-3+3 = 0+3 z=3