Math y^2 -28y+160=0 Factor and solve Asked by AnneS2 on 08 Oct 04:46 Last updated by anonymous on 09 Oct 15:39
y^2 -28y+160=0 (y )(y ) ( -20)( -8)=0 (y-20) (y-8) = 0 Solve: (y-20)=0 y-20+20=0+20 y=20 Solve: (y-8) = 0 y-8+8 = 0+8 y=8