Math

y^2 - 20y + 64 = 0 Factor and solve

Asked by AnneS2 on 08 Oct 04:47

Last updated by anonymous on 09 Oct 15:29

1 Answers

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Answered by CherieS on 09 Oct 15:29

y^2 - 20y + 64 = 0

(y )(y ) ( -16)( -4)=0

(y-16) (y-4) = 0

Solve:

(y-16)=0

y-16+16=0+16

y=16

Solve:

(y-4) = 0

y-4+4 = 0+4

y=4