Math
(x^3 +13x^2 +39x-5)/(x+5)
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Asked by
AnneS2
Last updated by
anonymous
(x^3 +13x^2 +39x-5)/(x+5)
=x^2(x+5)=x^3+5 x^2
x^3 +13x^2 +39x-5-x^3-5x^2=8x^2+39x
=8x(x+5)=8 x^2+40 x
8x^2+39x-8x^2-40x-5=-1x-5
=-1(x+5)=-x-5
-1x-5+x+5=0
answer: x^2+8x-1 r0