Math
Solve for each system 4u+3v+2y=44, 3u+4v = 36, 3u=12
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Asked by
AnneS2
Last updated by
anonymous
3u=12
3u/3=12/3
u=4
3u+4v = 36
3(4)+4v = 36
12+4v = 36
12+4v-12 = 36-12
4v=24
4v/4=24/4
v=6
4u+3v+2y=44
4(4)+3(6)+2y=44
16+18+2y=44
34+2y=44
34+2y-34=44-34
2y=10
2y/2=10/2
y=5