Math
Solve for each system: 2v+4x+2z = 24, 4v+x = 16, 6v=18

Asked by
AnneS2
Last updated by
anonymous
6v=18
6v/6=18/6
v=3
4v+x = 16
4(3)+x = 16
12+x = 16
12+x-12 = 16-12
x=4
2v+4x+2z = 24
2(3)+4(4)+2z = 24
6+16+2z = 24
22+2z = 24
22+2z-22 = 24-22
2z=2
2z/2=2/2
z=1