Math
Solve for both systems: z+2x=29 and 3z + 2x = 43

Asked by
AnneS2
Last updated by
anonymous
z+2x=29
z+2x-2x=29-2x
z=29-2x
3z + 2x = 43
3(29-2x) + 2x = 43
3(29) (3)(-2x) + 2x = 43
87-6x+ 2x = 43
87-4x= 43
87-4x-87= 43-87
-4x=-44
-4x/-4=-44/-4
x=11
z=29-2x
z=29-2(11)
z=29-22=7