Math
Solve for both systems z+2x=23 and 2z + 3x = 44
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Asked by
AnneS2
Last updated by
anonymous
z+2x=23
z+2x-2x=23-2x
z=23-2x
2z + 3x = 44
2(23-2x) + 3x = 44
2(23) (2)(-2x) + 3x = 44
46-4x+3x=44
46-x=44
46-x-46=44-46
-x=-2
-x/-1=-2/-1
x=2
z=23-2x
z=23-2(2)
z=23-4=19