Math
Solve for both systems z + y = 12 and 11z+6y=132
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Asked by
AnneS2
Last updated by
anonymous
z + y = 12
z-z + y = 12-z
y = 12-z
11z+6y=132
11z+6(12-z)=132
11z+6(12) (6)(-z)=132
11z+72-6z=132
5z+72=132
5z+72-72=132-72
5z=60
5z/5=60/5
z=12
y = 12-z
y = 12-12=0