Math
Solve for both systems: y+9z=27 and z + 3y = 3

Asked by
AnneS2
Last updated by
anonymous
y+9z=27
y+9z-9z=27-9z
y=27-9z
z + 3y = 3
z + 3(27-9z) = 3
z + 3(27) (3)(-9z) = 3
z+81-27z=3
81-26z=3
81-26z-81=3-81
-26z=-78
-26z/-26=-78/-26
z=3
y=27-9z
y=27-9(3)
y=27-27=0