Math Solve for both systems y+7z=52 and 2y + z = 16 Asked by AnneS2 on 03 Sep 07:11 Last updated by anonymous on 04 Sep 23:53
y+7z=52 y+7z-7z=52-7z y=52-7z 2y + z = 16 2(52-7z) + z = 16 2(52) (2)(-7z) + z = 16 104-14z+ z = 16 104-13z = 16 104-13z-104 = 16-104 -13z=-88 -13z/-13=-88/-13 z=6.77 y=52-7z y=52-7(6.77) y=52-47.38=4.62