Math
Solve for both systems x+7z=126 and 2x + 4z = 82
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Asked by
AnneS2
Last updated by
anonymous
x+7z=126
x+7z-7z=126-7z
x=126-7z
2x + 4z = 82
2(126-7z) + 4z = 82
2(126) (2)(-7z) + 4z = 82
252-14z+ 4z = 82
252-10z= 82
252-10z-252= 82-252
-10z=-170
-10z/-10=-170/-10
z=17
x=126-7z
x=126-7(17)
x=126-119=7