Math Solve for both systems: 7y+z=42 and 2y + z = 12 Asked by AnneS2 on 02 Oct 07:09 Last updated by anonymous on 03 Oct 11:13
7y+z=42 7y-7y+z=42-7y z=42-7y 2y + z = 12 2y + 42-7y = 12 42-5y = 12 42-5y-42 = 12-42 -5y=-30 -5y/-5=-30/-5 y=6 z=42-7y z=42-7(6) z=42-42=0