Math
Solve for both systems: 7y+z=42 and 2y + z = 12

Asked by
AnneS2
Last updated by
anonymous
7y+z=42
7y-7y+z=42-7y
z=42-7y
2y + z = 12
2y + 42-7y = 12
42-5y = 12
42-5y-42 = 12-42
-5y=-30
-5y/-5=-30/-5
y=6
z=42-7y
z=42-7(6)
z=42-42=0