Math
Solve for both systems: 6z+5y=80 and 6z+2y=50

Asked by
AnneS2
Last updated by
anonymous
6z+2y=50
6z-6z+2y=50-6z
2y=50-6z
2y/2=50-6z/2
y=25-3z
6z+5y=80
6z+5(25-3z)=80
6z+5(25) (5)(-3z)=80
6z+125-15z=80
125-9z=80
125-9z-125=80-125
-9z=-45
-9z/-9=-45/-9
z=5
y=25-3z
y=25-3(5)
y=25-15=10