Math Solve for both systems: 6z+5y=80 and 6z+2y=50 Asked by AnneS2 on 16 Sep 06:27 Last updated by anonymous on 17 Sep 20:10
6z+2y=50 6z-6z+2y=50-6z 2y=50-6z 2y/2=50-6z/2 y=25-3z 6z+5y=80 6z+5(25-3z)=80 6z+5(25) (5)(-3z)=80 6z+125-15z=80 125-9z=80 125-9z-125=80-125 -9z=-45 -9z/-9=-45/-9 z=5 y=25-3z y=25-3(5) y=25-15=10