Math Solve for both systems 6z+2y=92 and 5z + 5y = 80 Asked by AnneS2 on 22 Jul 04:58 Last updated by anonymous on 24 Jul 11:51
5z + 5y = 80 5z -5z+ 5y = 80-5z 5y = 80-5z 5y/5= 80-5z/5 y=16-z 6z+2y=92 6z+2(16-z)=92 6z+2(16) (2)(-z)=92 6z+32-2z=92 4z+32=92 4z+32-32=92-32 4z=60 4z/4=60/4 z=15 y=16-z y=16-15=1