Math
Solve for both systems 6y+2z=38 and 2y - 2z = 2

Asked by
AnneS2
Last updated by
anonymous
2y - 2z = 2
2y - 2z +2z= 2+2z
2y= 2+2z
2y/2= 2+2z/2
y=1+z
6y+2z=38
6(1+z)+2z=38
6(1) (6)(+z)+2z=38
6+6z+2z=38
6+8z=38
6+8z-6=38-6
8z=32
8z/8=32/8
z=4
y=1+z
y=1+4
y=5