Math Solve for both systems 6y+2z=38 and 2y - 2z = 2 Asked by AnneS2 on 12 Sep 03:18 Last updated by anonymous on 14 Sep 01:09
2y - 2z = 2 2y - 2z +2z= 2+2z 2y= 2+2z 2y/2= 2+2z/2 y=1+z 6y+2z=38 6(1+z)+2z=38 6(1) (6)(+z)+2z=38 6+6z+2z=38 6+8z=38 6+8z-6=38-6 8z=32 8z/8=32/8 z=4 y=1+z y=1+4 y=5