Solve for both systems: 5y+4z=100 and 5y + 3z = 95

Asked by AnneS2 on 23 Sep 05:43

Last updated by anonymous on 25 Sep 11:16

Answered by CherieS on 25 Sep 11:16

5y+4z=100

5y-5y+4z=100-5y

4z=100-5y

4z/4=100-5y/4

z=25-1.25y

5y + 3z = 95

5y + 3(25-1.25y) = 95

5y + 3(25) (3)(-1.25y) = 95

5y + 75 -3.75y= 95

1.25y + 75 = 95

1.25y + 75-75 = 95-75

1.25y=20

1.25y/1.25=20/1.25

y=16

z=25-1.25y

z=25-1.25(16)

z=25-20=5