Math
Solve for both systems 5x+7z=14 and 12x+2z=4

Asked by
AnneS2
Last updated by
anonymous
12x+2z=4
12x-12x+2z=4-12x
2z=4-12x
2z/2=4-12x/2
z=2-6x
5x+7z=14
5x+7(2-6x)=14
5x+7(2) (7)(-6x)=14
5x+14-42x=14
14-37x=14
14-37x-14=14-14
-37x=0
-37x/-37=0/-37
x=0
z=2-6x
z=2-6(0)
z=2-2=2