Math
Solve for both systems 5x + 2y = 12 and 3x + 2y = 12

Asked by
AnneS2
Last updated by
anonymous
5x + 2y = 12
5x -5x+ 2y = 12-5x
2y = 12-5x
2y/2 = 12-5x/2
y=6-2.5x
3x + 2y = 12
3x + 2(6-2.5x) = 12
3x + 2(6) (2)(-2.5x) = 12
3x+12-5x=12
12-3x=12
12-3x-12=12-12
-3x=0
-3x/-3=0/-3
x=0
y=6-2.5x
y=6-2.5(0)
y=6-0=6