Math Solve for both systems 4y+2x=48 and 4y + 3x = 58 Asked by AnneS2 on 03 Sep 07:10 Last updated by anonymous on 04 Sep 23:58
4y+2x=48 4y-4y+2x=48 -4y 2x=48 -4y 2x/2=48 -4y/2 x=24-2y 4y + 3x = 58 4y + 3(24-2y) = 58 4y + 3(24) (3)(-2y) = 58 4y +72-6y = 58 72-2y = 58 72-2y-72 = 58-72 -2y=-14 -2y/-2=-14/-2 y=7 x=24-2y x=24-2(7) x=24-14=10