Math
Solve for both systems 4y+2x=48 and 4y + 3x = 58
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Asked by
AnneS2
Last updated by
anonymous
4y+2x=48
4y-4y+2x=48 -4y
2x=48 -4y
2x/2=48 -4y/2
x=24-2y
4y + 3x = 58
4y + 3(24-2y) = 58
4y + 3(24) (3)(-2y) = 58
4y +72-6y = 58
72-2y = 58
72-2y-72 = 58-72
-2y=-14
-2y/-2=-14/-2
y=7
x=24-2y
x=24-2(7)
x=24-14=10