Math Solve for both systems: 3y + 2z = 25 and 13y-2z=23 Asked by AnneS2 on 16 Sep 06:16 Last updated by anonymous on 18 Sep 12:02
3y + 2z = 25 3y-3y + 2z = 25-3y 2z = 25-3y 2z/2 = 25-3y/2 z=12.5-1.5y 13y-2z=23 13y-2(12.5-1.5y)=23 13y-2(12.5) (-2)(-1.5y)=23 13y-25+3y=23 -25+16y=23 -25+16y+25=23+25 16y=48 16y/16=48/16 y=3 z=12.5-1.5y z=12.5-1.5(3) z=12.5-4.5=8