Math
Solve for both systems: 3y + 2z = 25 and 13y-2z=23
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Asked by
AnneS2
Last updated by
anonymous
3y + 2z = 25
3y-3y + 2z = 25-3y
2z = 25-3y
2z/2 = 25-3y/2
z=12.5-1.5y
13y-2z=23
13y-2(12.5-1.5y)=23
13y-2(12.5) (-2)(-1.5y)=23
13y-25+3y=23
-25+16y=23
-25+16y+25=23+25
16y=48
16y/16=48/16
y=3
z=12.5-1.5y
z=12.5-1.5(3)
z=12.5-4.5=8