Math
Solve for both systems 3x + y = 16 and 3x - y = 8

Asked by
AnneS2
Last updated by
anonymous
3x + y = 16
3x-3x + y = 16-3x
y = 16-3x
3x - y = 8
3x - (16-3x) = 8
3x - 16+3x = 8
6x-16=8
6x-16+16=8+16
6x=24
6x/6=24/6
x=4
y = 16-3x
y = 16-3(4)
y = 16-12=4