Solve for both systems: 3x + 4y = - 15 and 2x + 4y = - 10

2x + 4y = - 10

2x + 4y-4y = - 10-4y

2x= - 10-4y

2x/2= - 10-4y/2

x=-5+2y

3x + 4y = - 15

3(-5+2y) + 4y = - 15

3(-5) (3)(+2y) + 4y = - 15

-15+6y+4y=-15

-15+10y=-15

-15+10y+15=-15+15

10y=0

10y/10=0/10

y=0

x=-5+2y

x=-5+2(0)

x=-5+0=-5