Math Solve for both systems: 13z+12y=109 and 4z + 4y = 36 Asked by AnneS2 on 23 Sep 05:44 Last updated by anonymous on 25 Sep 10:43
4z + 4y = 36 4z-4z + 4y = 36-4z 4y = 36-4z 4y /4= 36-4z/4 y=9-z 13z+12y=109 13z+12(9-z)=109 13z+12(9) (12)(-z)=109 13z+108-12z=109 z+108=109 z+108-108=109-108 z=1 y=9-z y=9-1=8