Math
Solve for both systems: 13z+12y=109 and 4z + 4y = 36

Asked by
AnneS2
Last updated by
anonymous
4z + 4y = 36
4z-4z + 4y = 36-4z
4y = 36-4z
4y /4= 36-4z/4
y=9-z
13z+12y=109
13z+12(9-z)=109
13z+12(9) (12)(-z)=109
13z+108-12z=109
z+108=109
z+108-108=109-108
z=1
y=9-z
y=9-1=8