Math
Solve for both systems 10z+9y=183 and 9z + 3y = 129
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Asked by
AnneS2
Last updated by
anonymous
9z + 3y = 129
9z-9z + 3y = 129-9z
3y = 129-9z
3y/3 = 129-9z/3
y=43-3z
10z+9y=183
10z+9(43-3z)=183
10z+9(43) (9)(-3z)=183
10z+387-27z=183
387-17z=183
387-17z-387=183-387
-17z=-204
-17z/-17=-204/-17
z=12
y=43-3z
y=43-3(12)
y=43-36=7