Math
Solve for both systems 10z+2x=26 and 6z + 4x = 24
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Asked by
AnneS2
Last updated by
anonymous
10z+2x=26
10z-10z+2x=26 -10z
2x=26 -10z
2x/2=26 -10z/2
x=13-5z
6z + 4x = 24
6z + 4(13-5z) = 24
6z + 4(13) (4)(-5z) = 24
6z +52-20z= 24
52-14z= 24
52-14z-52= 24-52
-14z=-28
-14z/-14=-28/-14
z=2
x=13-5z
x=13-5(2)
x=13-10=3