Math
Solve for 3u+z=15 and u+2z = 10

Asked by
AnneS2
Last updated by
anonymous
u+2z = 10
u+2z-2z = 10-2z
u= 10-2z
3u+z=15
3(10-2z)+z=15
3(10) (3)(-2z)+z=15
30-6z+z=15
30-5z=15
30-5z-30=15-30
-5z=-15
-5z/-5=-15/-5
z=3
u= 10-2z
u= 10-2(3)
u= 10-6=4