Math (p^2-3p^4- 2) + (8p^2+ 4 + 9p^4) - (6p^2-7p + 5)= Asked by AnneS2 on 21 Sep 07:29 Last updated by anonymous on 22 Sep 11:12
(p^2-3p^4- 2) + (8p^2+ 4 + 9p^4) - (6p^2-7p + 5) p^2-3p^4- 2 + 8p^2+ 4 + 9p^4 - 6p^2 + 7p - 5 p^2 + 8p^2- 6p^2 -3p^4+ 9p^4 + 7p - 5- 2+ 4 3p^2 + 6p^4 + 7p - 3