Math Factor and check: x^2 -16x+64=0 Asked by AnneS2 on 12 Sep 03:21 Last updated by anonymous on 13 Sep 15:18
x^2 -16x+64=0 (x )(x ) ( -8)( -8)=0 (x-8)(x-8)=0 (x-8)^2 = 0 Check: (x-8)(x-8)=0 (x)(x) (x)(-8) (-8)(x) (-8)(-8)=0 x^2 -8x -8x +64=0 x^2 -16x +64=0