how long does it take a pot to go from 170 degrees to 110 degress in a fridge (37 degrees)?

This is determined using Newton's Law of Cooling - dT/dt=-k(T-a)

dT being the change in temperature

dt being the change in time

k being the proportional constant of the pot

T being the temperture at a given point in time

a being the constant temperature of the environment.

With what you have given us, the equation looks like this

60/dt=-k(170-37)

So it is quite difficult to solve for time when k is still a variable. Therefore simply plug in k(the proportional constant of the pot) and solve algebraically. The equation should be:

60/(-k(170-37))=dt

Hope this helps