8(z + 4) = 5(13 + z)

Holt McDougal Larson Pre-Algebra Common Core Edition page 135 number 36

Asked by Dee Dee on 12 Apr 09:12

Last updated by anonymous on 12 Apr 22:45

Answered by CherieS on 12 Apr 22:45

(8)(z) +(8)(4)=(5)(13) +(5)(z)

8z+32=65+5z

8z+32-32=65-32+5z

8z=33+5z

8z-5z=33+5z-5z

3z=33

3z/3=33/3

z=11