(7k^2 + 2k - 6) + (3k^2 - 11k - 8)

Holt McDougal Larson Algebra 1 Common Core Edition page 499 number 20

Asked by Dee Dee on 19 Mar 11:32

Last updated by anonymous on 20 Mar 11:19

Answered by CherieS on 20 Mar 11:19

10 k^2-9 k-14