4x^2 = 22x + 42

Holt McDougal Larson Algebra 1 Common Core Edition page 563 number 28

Asked by Dee Dee on 26 Mar 10:12

Last updated by anonymous on 27 Mar 12:04

Answered by CherieS on 27 Mar 12:04

4x^2 = 22x + 42

4^2-22x-42=22x+42-22x-42

4x^2-22x-42=0

2(x ) (2x ) ( -7) ( +3)

2(x-7)(2x+3)=0

Check:

2(x)(2x) (x)(+3) (-7)(2x) (-7)(+3)

2 2x^2 3x -14x -21

2(2x^2-11x-21)

4x^2-22x-42