Math

(9x^3z)/(9xzx)x

Asked by AnneS2 12 years ago 3/24/2013 6:41 AM

Last updated by anonymous 12 years ago 3/25/2013 11:20 PM

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Answered by CherieS 12 years ago 3/25/2013 11:20 PM

=(9x^3z)/(9xz*x)*x

=(9x^3z)/(9x^2z) *x

=9/9=1

=x^3z/x^2z=z/z=1

=x^3/x^2=x^3-2=x

=x*x

=x^2

=x^2