(9n^3 - 7n - 8) - (3n^3 + 6 - n^5) - (4n^5 + 2)

Asked by AnneS2 on 23 Sep 06:02

Last updated by anonymous on 24 Sep 13:07

Answered by CherieS on 24 Sep 13:07

(9n^3- 7n - 8) - (3n^3 + 6 - n^5) - (4n^5+ 2)

9n^3- 7n - 8 - 3n^3- 6 + n^5 - 4n^5- 2

9n^3- 3n^3 - 7n - 8- 2 + n^5 - 4n^5

6n^3 - 7n -10 - 3n^5