Math
(9n^3 - 7n - 8) - (3n^3 + 6 - n^5) - (4n^5 + 2)
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Asked by
AnneS2
Last updated by
anonymous
(9n^3- 7n - 8) - (3n^3 + 6 - n^5) - (4n^5+ 2)
9n^3- 7n - 8 - 3n^3- 6 + n^5 - 4n^5- 2
9n^3- 3n^3 - 7n - 8- 2 + n^5 - 4n^5
6n^3 - 7n -10 - 3n^5