Math 9 * (4 / 4) + 9^2 / 3= Asked by AnneS2 on 18 Aug 01:12 Last updated by anonymous on 20 Aug 06:47
PEMDAS=(), exponents, *,/, +, - =9 * (4 / 4) + 9^2 / 3 =9 * (1) + 9^2 / 3 =9 * (1) + 81 / 3 =9 * (1) + 27 =9 + 27 =36
