Math (8 + 2y^3 + 5y^4) - (3y^4 - 4y^2 - 7) + (6y^3 + 9y^2) Asked by AnneS2 on 29 Sep 04:50 Last updated by anonymous on 01 Oct 08:47
(8 + 2y^3 + 5y^4) - (3y^4 - 4y^2 - 7) + (6y^3 + 9y^2) 8 + 2y^3 + 5y^4 - 3y^4 + 4y^2 + 7 + 6y^3 + 9y^2 8+ 7 + 6y^3 + 2y^3 + 5y^4 - 3y^4 + 4y^2+9y^2 15 + 8y^3 + 2y^4 + 13y^2