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> (7y^3-5)+(3y^3-16)=
Math
(7y^3-5)+(3y^3-16)=
Asked by
AnneS2
on 25 Sep 03:38
Last updated by
anonymous
on 26 Sep 11:27
1
Answers
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Answered by
CherieS
on 26 Sep 11:27
(7y^3-5)+(3y^3-16)
7y^3-5 + 3y^3-16
7y^3+ 3y^3 -16-5
10y^3 -21