Math (7y^3 + 4y - 9) - (6y^3 + 8 + y^4) + (3y^4 + 5) Asked by AnneS2 on 03 Oct 07:21 Last updated by anonymous on 04 Oct 11:54
(7y^3 + 4y - 9) - (6y^3 + 8 + y^4) + (3y^4 + 5) 7y^3 + 4y - 9 - 6y^3 - 8 - y^4 + 3y^4 + 5 7y^3- 6y^3 + 4y - y^4 + 3y^4 + 5- 9 - 8 y^3 + 4y + 2y^4 -12