Math
(7y^3 + 4y - 9) - (6y^3 + 8 + y^4) + (3y^4 + 5)
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Asked by
AnneS2
Last updated by
anonymous
(7y^3 + 4y - 9) - (6y^3 + 8 + y^4) + (3y^4 + 5)
7y^3 + 4y - 9 - 6y^3 - 8 - y^4 + 3y^4 + 5
7y^3- 6y^3 + 4y - y^4 + 3y^4 + 5- 9 - 8
y^3 + 4y + 2y^4 -12