Math

(7 b - 8)^5, when b = 5 Evaluate

Asked by AnneS2 12 years ago 7/16/2013 2:29 AM

Last updated by anonymous 12 years ago 7/17/2013 1:40 PM

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Answered by CherieS 12 years ago 7/17/2013 1:40 PM

(7 b - 8)^5

(7*5 - 8)^5

(35 - 8)^5

(27)^5

14348907