Math
6y^2-46y+40=0
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Asked by
AnneS2
Last updated by
anonymous
6y^2-46y+40=0
2(3y^2-23y+20)
2 (y )(3y ) ( -1)( -20)
2(y-1)(3y-20)
Solve:
2(y-1)=0
2y (2)(-1)=0
2y-2=0
2y-2+2=0+2
2y=2
2y/2=2/2
y=1
Solve:
2(3y-20)=0
2(3y) (2)(-20)=0
6y-40=0
6y-40+40=0+40
6y=40
6y/6=40/6
y=20/3