64x^2 + 16x + 1 = 0

Asked by AnneS2 12 years ago 4/1/2013 5:00 AM

Last updated by anonymous 12 years ago 4/3/2013 10:10 PM

Answered by CherieS 12 years ago 4/3/2013 10:10 PM

64x^2 + 16x + 1 = 0

(8x )(8x ) ( +1)( +1)

(8x+1)(8x+1)=(8x+1)^2

Check:

(8x+1)(8x+1)

(8x)(8x) (8x)(1) (1)(8x) (1)(1)

64x^2 +8x +8x +1

64x^2 +16x +1