Math
5x+10z=150 4x + 4z = 92

Asked by
AnneS2
Last updated by
anonymous
5x+10z=150
5x+10z-10z=150-10z
5x=150-10z
5x/5=150-10z/5
x=30-2z
4x + 4z = 92 sub in x
4(30-2z)+4z=92 solve for z
120-8z+4z=92
120-4z=92
120-120-4z=92-120
-4z=-28
-4z/-4=-28/-4
z=7
x=30-2z sub in z=7
x=30-2(7)
x=30-14
x=16