Math
4y+z=56 3y + 6z = 63

Asked by
AnneS2
Last updated by
anonymous
3y + 6z = 63
3y+6z-6z=63-6z
3y=63-6z
3y/3=63-6z/3
y=21-2z
4y+z=56 sub in y and solve for z
4(21-2z)+z=56
84-8z+z=56
84-7z=56
84-84-7z=56-84
-7z=-28
-7z/-7=-28/-7
z=4
y=21-2z
y=21-2(4)
y=21-8
y=13