Math

4x^2 - 8x - 4 = 0 Factor and solve

Asked by AnneS2 on 22 Jun 11:48

Last updated by anonymous on 23 Jun 10:51

1 Answers

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Answered by CherieS on 23 Jun 10:51

4x^2 - 8x - 4 = 0

4(x^2-2x-1)=0

4 ( (x )(x ) ( -2)( -1))=0

4 ((x-2) (x-1)) = 0

Solve:

4(x-2)=0

4(x) (4)(-2)=0

4x-8=0

4x-8+8=0+8

4x=8

4x/4=8/4

x=2

Solve:

4(x-1) = 0

4(x) (4)(-1) = 0

4x-4=0

4x-4+4=0+4

4x=4

4x/4=4/4

x=1

x=2,1