Math
4x^2 -38x+84=0
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Asked by
AnneS2
Last updated by
anonymous
4x^2 -38x+84=0
2(2x^2-19x+42)
2 (x )(2x ) ( -6)(x -7)
2(x-6)(2x-7)
Solve:
2(x-6)=0
2(x) (2)(-6)=0
2x-12=0
2x-12+12=0+12
2x=12
2x/2=12/2
x=6
Solve:
2(2x-7)=0
2(2x) (2)(-7)=0
4x-14=0
4x-14+14=0+14
4x=14
4x/4=14/4
x=14/4 =7/2