Math
3r^2 -16r-7=5 Solve
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Asked by
AnneS2
Last updated by
anonymous
3r^2 -16r-7=5
3r^2 -16r-7-5=5-5
3r^2 -16r-12=0
(r )(3r ) ( -6)( +2)=0
(r-6) (3 r+2) = 0
Solve:
(r-6)=0
r-6+6=0+6
r=6
Solve:
(3 r+2) = 0
3r+2-2=0-2
3r=-2
3r/3=-2/3
r=-2/3