Math 3c+4u=33 6c+3u=36 Solve for each system Asked by AnneS2 on 18 Jul 05:21 Last updated by anonymous on 24 Aug 23:30
6c+3u=36 6c-6c+3u=36-6c 3u=36-6c 3u/3=36-6c/3 u=12-2c 3c+4u=33 3c+4(12-2c)=33 3c+4(12) (4)(-2c)=33 3c+48-8c=33 48-5c=33 48-5c-48=33-48 -5c=-15 -5c/-5=-15/-5 c=3 u=12-2c u=12-2(3) u=12-6=6