Math
3a+5u=17 and 2a+u=9 Solve for each system
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Asked by
AnneS2
Last updated by
anonymous
2a+u=9
2a-2a+u=9-2a
u=9-2a
3a+5u=17
3a+5(9-2a)=17
3a+5(9) (5)(-2a)=17
3a+45-10a=17
45-7a=17
45-7a-45=17-45
-7a=-31
-7a/-7=-31/-7
a=4.43
u=9-2a
u=9-2(4.43)
u=9-8.86=.14