Math 2y^2 +4y+2=0 Factor and check Asked by AnneS2 on 03 Sep 07:14 Last updated by anonymous on 04 Sep 14:19
2y^2 +4y+2=0 2(y^2 +2y+1)=0 2 (y )(y ) ( +1)( +1=0 2(y+1)(y+1)=0 2 (y+1)^2 = 0 Check: 2(y+1)(y+1)=0 2(y)(y) (y)(1) (1)(y) (1)(1)=0 2 (y^2+ 1y +1y +1)=0 2 (y^2 +2y +1)=0 2y^2 +4y +2=0